Solve Equations

Solve Equations 

Problem:

Given two equations EQN1 and EQN2 containing the values of x co-efficient, y co-efficient and the resulting constant, the program must print the value of x and y separated by a space. 

Input Format: 

The first line contains the equation EQN1. The second line contains the equation EQN2. 

Output Format: 

The first line contains the value of x and y separated by a space. 

Boundary Conditions: 

1 <= Co-efficient values <= 1000 

Example Input/Output 1: 

Input: 

5x+2y=14 

-4y+3x=-2 

Output: 

2 2 

Example Input/Output 2: 

Input: 

4Y-5X=17 

3X+4Y=9 

Output: 

-1 3

Program:

def extractnum(s): 

    a = "" 

    k = []

    for i in s: 

        if i not in "xy= ":

            a += i 

        else:

            if a!= "": 

                k.append(int(a))

            a = ""    

    if a != "":

        k.append(int(a))

    return k 

    

def extractorder(s): 

    a = ""

    for i in s: 

        if i in "xy": 

            a += i 

    return a 

    

s = input().strip().lower()

t = input().strip().lower()

a = extractnum(s)

b = extractnum(t)

c = extractorder(s) 

d = extractorder(t) 

if c == "yx": 

    a[0],a[1] = a[1],a[0] 

if d == "yx":

    b[0],b[1] = b[1],b[0] 


# to find x 

p, q = a.copy(), b.copy()

mul1,mul2 = p[1],q[1]

ans =[]

for i in range(3):

    q[i] = q[i]*mul1

    p[i] = p[i]*mul2 

    ans.append(q[i]-p[i])

print(ans[-1]//ans[0],end=" ") 


# to find y

p,q = a.copy(), b.copy() 

mul1,mul2 = p[0],q[0] 

ans = [] 

for i in range(3): 

    q[i] = q[i]*mul1 

    p[i] = p[i]*mul2

    ans.append(q[i]-p[i]) 

print(ans[-1]//ans[1])    

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