Next Date with Same Weekday

Next Date with Same Weekday

Problem: 

Calculate the date of next 7th day from the given date. 

Input: 

31-03-2019 

Output: 

07-04-2019

Program:

def leap(y): 

    return (y%400==0 or (y%4==0 and y%100!=0))

s = list(map(int,input().split("-")))

s[0] += 7 

a = [1,3,5,7,8,10,12]

b = [2]

c = [4,6,9,11] 

if s[1] in a and s[0] > 31:

    s[0] = s[0] % 31 

    s[1] += 1 

    if s[1] > 12: 

        s[1] = s[1]%12 

        s[2] += 1 

if s[1] in c and s[0] > 30: 

    s[0] = s[0] % 30

    s[1] += 1 

if s[1] in b: 

    if leap(s[2]) and s[0] > 29: 

        s[0] = s[0] % 29 

        s[1] += 1 

    elif not(leap(s[2])) and s[0] > 28: 

        s[0] = s[0] % 28 

        s[1] += 1     

print("%.02d"%s[0],"%.02d"%s[1],"%.02d"%s[2],sep="-")

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